0.25x^2-6x+20=0

Solution for 0.25x^2-6x+20=0 equation:

0.25x^2-6x+20=0

a = 0.25; b = -6; c = +20;
Δ = b2-4ac
Δ = -62-4·0.25·20
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4}{2*0.25}=\frac{2}{0.5}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4}{2*0.25}=\frac{10}{0.5}
=20
$